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How To Open File And Load Contents Into A Variable

     

ktsirig

12:44 am on Dec 9, 2012 (gmt 0)

5+ Year Member



Hi,

in my PHP webpage I specify 3 files, like:


$first_file = $_POST["one"];
$second_file = $_POST["two"];
$third_file = $_POST["three"];


then I have a JS fuction, that in some points, needs to open each file and store the data of each file into a variable. My questions are 2:
First, how do I save all data of each text file into a JS variable?
Second, the part of the Js function which has these variables looks like this:


series:
[
{
name: 'ONE',
color: 'blue',
data:
[
HERE WE SHOULD PLACE ALL DATA FROM FILE 1
]
},

{
name: 'TWO',
color: 'yellow',
data:
[
HERE WE SHOULD PLACE ALL DATA FROM FILE 2
]
},

{
name: 'THREE',
color: 'red',
data:
[
HERE WE SHOULD PLACE ALL DATA FROM FILE 3
]
}
]


Can you please help me, how I can put the data of each file into the correct place? I am new to JS and came across a helpful snipet of code, but I do not know how I can place my data inside the JS code so as to use them.

Thanks a lot!

swa66

12:31 pm on Dec 9, 2012 (gmt 0)

WebmasterWorld Senior Member swa66 is a WebmasterWorld Top Contributor of All Time 10+ Year Member



You're leaving out some crucial info.

Where are the files stored ? (server? Accessible via the web (i.e. does it have e.g. a URL)? , client? )
When do you want the contents to be loaded ? "at some point" suggests that you want to wait, ...
 

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