I'd try escaping the quotes you wish to have appear in the string. You can also use the casting operator, (string), to assure that your variable is being converted, though that shouldn't be the problem.
marcus76
1:25 pm on Aug 19, 2004 (gmt 0)
hey Rambo, thanks for your reply - i'm not so sure of the Escape syntax? would you mind posting an example?
thanks
coopster
3:39 pm on Aug 19, 2004 (gmt 0)
Actually, you should be getting a PHP parse error. Escaping the string as described...