parseInt() problem

Tiny annoying problem....

[tomda]

Hi, I have the following javascript that check if the value is between 3 and 75.

if (parseInt(document.form1.form_disptopics.value)<"3") {return false;}
if (parseInt(document.form1.form_disptopics.value)>"75") {return false;}

I have added parseInt (after consulting my Javascript Bible) because I noticed that entering "0002" was returning "true".

But it seems that parseInt() is not what I am looking for since for example:
A/ "0076" return "true" (value after parseInt() being "62").
B/ "0762" return "true" (value after parseInt() being "498").

Any existing javascript function (similar to intval() in PHP) that return the absolute value of any number (Including numbers like "000025")

Thanks

[jshanman]

try this:

parseInt('000025',10);
parseInt('0076',10);
parseInt('0762',10);

Use "10" as the second argument and it forces parseInt to use a base 10 when attempting to parse the number.

- JS

[visionmonster]

parseInt is pretty powerful:

i believe the leading zero makes it default to base 8
parseInt("0076",10) = 76;
parseInt("0076",8) = 62;

binary: parseInt("0100",2) = 4

hexadecimal: parseInt("ff",16) = 255;

[tomda]

Thanks...
This seems to be the solution to my problem.
Much appreciated.

[vincevincevince]

It is worth remembering that a leading 0 is not just ignored in javascript in most functions. 011!= 11