How to extract values from html code using php?

[Thaparian]

Hi,

I need to extract link url and image url from a peace of html code.

Sample HTML code

<a href="link to full size image"><img src="medium size image path here"/></a>

Or

<img src="medium size image path here" alt ="" />

If a link is present, I need the full size image url, otherwise I need the medium size image path.


This is the code that I made, but I think this is not the right way to get this done.

<?php
$test="html code here";
$doc=new DOMDocument();
$doc->loadHTML("$test");
$xml=simplexml_import_dom($doc);

$images=$xml->xpath('//img');

foreach ($images as $img) {

$thumburl = $img['src'];
}

$href = preg_match('/\shref="(?<href>[^"]+)"/', $test, $match);


if ($href!="") {
$href = $match[1];
echo $href;
}
else {
echo $thumburl;
}
?>

Please help.

[brotherhood of LAN]

It looks like you can avoid using regex in this example. Try this code.

test "; $doc=new DOMDocument(); $doc->loadHTML($test); // Get all tags $a = $doc->getElementsByTagName('a'); // Count of tags $alen = $a->length; for($i = 0;$i < $alen;$i++) { // return href if it exists into $href if($a->item($i)->hasAttribute('href')) $href = $a->item($i)->getAttribute('href'); /* return src attribute of image into $src if 1) parent element is 2) element is 3) src attribute exists */ if($a->item($i)->haschildNodes() && $a->item($i)->firstChild->nodeName == 'img' && $a->item($i)->firstChild->hasAttribute('src')) $src = $a->item($i)->firstChild->getAttribute('src'); } ?>

You'll need to replace the &;&; with && as the syntax highlighter has altered it.