Thanks Penders,
yes $row["conditions"] does have a link in the database, this is the query that works perfect.
<select name="menu1" onChange="MM_jumpMenu('parent',this,0)"> <option>Please select</option>
<?php
$query = " SELECT id_propiedad, conditions FROM casa order by id_propiedad ";
$result = mysql_query ($query);
while ($row = mysql_fetch_array($result)) {
?>
<option value="<?php print($row["conditions"]);?>"><?php print($row["id_propiedad"]); ?></option>
<?php
}
?>
</select>
This is what I want to do, and now get less errors:
<select name="menu1" onChange="MM_jumpMenu('parent',this,0)"> <option>Please select</option>
<?php
include("conex/conexion.php");
$query = " SELECT nombre FROM Casas_alquilar order by nombre ";
$result = mysql_query ($query);
while ($row = mysql_fetch_array($result)) {
?>
<option value=<?php print '<a href=ver_casas_alquilar.php?nombre='.$row["nombre"].';> ?> > <?php print($row["nombre"]); ?> <?php </a>' ?></option>
<?php
}
?>
</select>
What you say at the end I dont understand what to do. What I done is to put $row["nombre"] in the option twice, the first is to pass the id and the link by the url, the second is to have the name in the option list.
Thanks.
Helen
