Undefined Offset

[Saboi]

Hello guys,

I have the following code and i need assistance getting over the undefined offset error.

Here is the logic. Someone types in something like Bank[space]forename surname. This they send to the php code for processing.

I get undefined offset errors when message sent does not have the three needed variables. I seek advise on how to work around this. Would like to know how input even with one variable can be handled without displaying the undefined offset message.

<?php
02 
03/* Getting sender's phone number and message text */
04 
05$price = "k230,000";
06 
07$price2 = "k1.8m";
08 
09/*$senderPhone = $_POST['sender'];*/
10 
11$messageText = $_POST['message'];
12 
13$variables = explode(" ","$messageText ");
14 
15$msg_code = strtoupper($variables[0]);
16 
17$forename = ucfirst($variables[1]);
18 
19$surname = ucfirst($variables[2]);
20 
21$message1 = "Hello $surname";
22 
23$message2 = "Hello $forename";
24 
25$message_type = "header('Content-Type: text/plain; charset=utf-8')";
26 
27if( $msg_code == ""){ $note = "Invalid SMS"; exit();}
28if( $forename == "") { $note = "Invalid SMS"; exit();}
29if( $surname == "") { $note = "Invalid SMS"; exit();}
30 
31if ($msg_code == "Bank")
32 
33  {
34 
35    if( $forename == "") { exit();}
36 
37    if( $surname == "") { $note = "Invalid SMS"; exit();}
38 
39    else
40 
41    {  $file = "bank.txt";
42 
43      $file_content = file_get_contents($file);
44 
45      $addition = $file_content + 1;
46 
47      if($file_content<=3)
48 
49        {
50     
51           
52          $senderPhone;
53          $message_type;
54          echo $message1;
55     
56        }
57    }
58 
59     
60  }
61 
62elseif($msg_code == "airport")
63 
64  {
65 
66    if( $forename == "") { $note = "Invalid SMS"; exit();}
67 
68    if( $surname == "") { $note = "Invalid SMS"; exit();}
69 
70    else
71 
72    {  $file = "airport.txt";
73 
74      $file_content = file_get_contents($file);
75 
76      $addition = $file_content + 1;
77 
78      if($file_content<=3)
79 
80        {
81     
82          $senderPhone;
83          $message_type;
84          echo $message2;
85     
86        }
87    }
88 
89     
90  }
91 
92 
93 
94?>

[coopster]

input type checkbox on a form will not return the variable name if nothing was checked and then the form was submitted. You need to check for the existence of a (potential) user-supplied variable before using it otherwise you will get warning errors. Use the PHP isset() function to check for the existence of an index (offset) in your arrays.

[rocknbil]

list($errors,$msg_code,$forename,$surname) = check_message($messageText); 
if ($errors) { echo $errors; exit; } // or return to form. 
// 
function check_message ($vars) { 
 if (! preg_match('/[\d\w]+/',$vars)) { return "<p>No value for message text.</p>"; } 
 $vars = explode(" ",$vars); 
 $errList = null; 
 for ($i=0;$i<3;$i++) { 
 $non_zero_index=$i+1; 
 if (! isset($vars[$i]) or ! preg_match('/[\w\d]+/i',$vars[$i])) { 
 $errList .= "<p>Variable number $non_zero_index is missing.</p>"; 
 } 
 } 
 if ($errList) { return $errList; } 
 else { return ($errList,strtoupper($vars[0]),ucfirst($vars[1]),ucfirst($vars[2]); } 
}