PHP OOP question

[L33t_J0rdan]

Hi there guys,
Okay, I always wondered this, but if I declared like:

$it = include(config.php);

Could I then go onto say:

if($it -> $billy == "hello") {
echo $it -> $billy;
} else {
destroy_SESSION();
}

billy being declared in the file, config.
I've really wondered this for a while.

[Matthew1980]

Hi there l33t_jordan

You would need to declare the instance of the class first before you can echo a var ;-)

Hope that helps you a bit, happy coding and welcome to the forum too.

Cheers,
MRb

[Matthew1980]

Hi there l33t_jordan

The above syntax would return an error anyway because your accessing the object incorrectly.

Wrong:
$var->$name;

Right:
$var->name;

Just thought i would mention this.

Cheers,
MRb

[jatar_k]

it's an odd thing, I don't think it would work

you could include the contents of the file then preg_match it maybe but then it wouldn't be executed

if you include the file normally the vars that are initialized are within scope of the including script so just saying

if($billy == "hello") {
echo $billy;
} else {
destroy_SESSION();
}

would be adequate.

unless there is some other reason for the approach that I am not seeing.

[L33t_J0rdan]

Thank you, guys. I have just wondered this, because I'm coding a 'habbo staff panel' for a client. Taking a look at other DJ panels show they use OOP but I can't find the root of the declaration. You guys can call me Jordan. And thanks again!

[penders]

If your config.php script returns an instance of a class that contains billy as a public property, then this would work...

$it = include(config.php);  
if ($it->billy == "hello") {  
 echo $it->billy;  
} else {  
 destroy_SESSION();  
}

NB: Corrected '$' in class property, as per Matthew1980's post above