<ul class="subjects">
<?php
$subject_set = mysql_query("SELECT * FROM galerija", $connection);
if (!$subject_set) {
die("Database query failed: " . mysql_error());
}
while ($subject = mysql_fetch_array($subject_set)) {
echo "<li>{$subject["ime"]}</li>"."<br>";
$page_set = mysql_query("SELECT * FROM slike WHERE id_gal = {$subject["id_gal"]}", $connection);
if (!$page_set) {
die("Database query failed: " . mysql_error());
}
echo "<ul class=\"pages\">";
while ($page = mysql_fetch_array($page_set)) {
echo "<li><img width=120 height=80 src=admin/galerija/".$page[slika1]."/></a> <img width=120 height=80 src=admin/galerija/".$page[slika2]." /> <img width=120 height=80 src=admin/galerija/".$page[slika3]." /></li>"."<br>";
echo "<li><img width=120 height=80 src=admin/galerija/".$page[slika4]." /> <img width=120 height=80 src=admin/galerija/".$page[slika5]." /> <img width=120 height=80 src=admin/galerija/".$page[slika6]." /></li>"."<br>";
echo "<li><img width=120 height=80 src=admin/galerija/".$page[slika7]." /> <img width=120 height=80 src=admin/galerija/".$page[slika8]." /> <img width=120 height=80 src=admin/galerija/".$page[slika9]." /></li>"."<br>";
}
echo "</ul>";
}
?>
</ul>
Now i wanna this picture to show with lightbox.js. How?