Variable/string issue

[Lived]

$Name = implode (' ¦¦ ', $array);
echo $Name;

This code will output :

something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4

and if i use $Name in this code nothing happen:

switch($something) :
case ($Name):
echo 'You got it!';
endswitch;

But if i use this code it works perfect:

switch($something) :
case (something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4):
echo 'You got it!';
endswitch;

I hope somebody understand me and my problem :)

[sonjay]

Where is the value of $something being set?

[Lived]

while($row = mysql_fetch_assoc($getName)){
$array[] = $row['something'] ;
}

[penders]

case (something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4):

Presumably you mean... ?

case ("something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4"):

Presumably $Name is still in scope at the point you test it?

[Lived]

while($row = mysql_fetch_assoc($getName)){
$array[] = $row['something'] ;
}

$Name = implode (' ¦¦ ', $array);
echo $Name;

switch($something) :
case ($Name):
echo 'You got it!';
endswitch;

will output nothing! But if i use the string directly in the code it works....

switch($something) :
case (something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4):
echo 'You got it!';
endswitch;

[penders]

(Note: This forum converts the pipe character into a split vertical bar character - just in case you try copying code back from this forum!)

case (something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4):

This line not valid PHP - you'll get a (fatal) parse error (which I assume you are not getting?!) - you'll need to surround your string value in quotes (either single or double), which I guess you must already be doing? Anyway...

Both your code snippets should give the same result - they should both be successful! Either testing the value of $Name or using the value directly should not matter. So, there must be something different between the values of $something and $Name when they are compared.

What do you get if you try this:

if ($Name == $something) { 
 echo "<p>You got it!</p>"; 
} else { 
 echo "<p>Oh no you didn't!<br>"; 
 echo "Name = $Name<br>"; 
 echo "something = $something</p>"; 
}

[Lived]

If i test your code it fail and give:

Oh no you didn't it!
Name = something1
something = 'something1' ¦¦ 'something2' ¦¦ 'somthing3' ¦¦ 'somthing4'

Pretty wierd and i have no clue why it don't work!

[Lived]

$Name == 'something1' ¦¦ 'something2' ¦¦ 'somthing3' ¦¦ 'somthing4'

will output:

You got it!

[penders]

Ok, so now you have single quotes around your somethingN values which you didn't have in the beginning - but seems to be correct?!

Also, in the beginning, you state:

echo $Name;
This code will output :
something1 ¦¦ something2 ¦¦ something3 ¦¦ somthing4

But in the code above $Name outputs:

something1

Something is obviously happening between your echo and switch statements? Is this all in the same code block? Is $Name in scope (my original question)?

$array[] = $row['something'] ;

Is this from your actual code? It may not throw an error, but using the variable $array as your array variable is bad programming practice and could lead to confusion with PHP's built in language constructs.

As sonjay asked above, "Where is the value of $something being set?"

You could post a more complete code example...

[Lived]

Here is the complete code i want to use:

while($row = mysql_fetch_assoc($getName)){
$array[] = $row['something'] ;
}

$Name = implode (' ¦¦ ', $array);

switch($something) :
case ($Name): //here is where the string goes
echo 'You got it!';
endswitch;

What i want is to pick some values from an database and use in a case statment....

[sonjay]

So where is $something being set? Try this and see if $something and $Name are what you expect them to be:

while($row = mysql_fetch_assoc($getName)){
$array[] = $row['something'] ;
}
$Name = implode (' ¦¦ ', $array); 
echo "something: $something<br>";
echo "Name: $Name";

[Lived]

When i echo the string it's look like it should, but it don't work as a string when i try to use it in the code.

echo $string; OK

if{something == $string} FAIL

[Lived]

My misstake did cause my problem....
case ($Name):
should be
case ($Name = $something):

Anyway thanx for your time.....

[penders]

case ($Name = $something):

This is not correct. This assigns (single equals) $something to $Name and so will always evaluate to true (giving you the result you are expecting).

If anything you should being using the comparison operator (double equals):

case ($Name == $something):

But this is the same as you original code:

switch ($something): 
case ($Name): // etc.

[penders]

This assigns (single equals) $something to $Name and so will always evaluate to true...

(...providing $something evaluates to true)