Parsing error I can't solve

[Sandd]

I query a MySQL table for $row['gender'] which returns b or g depending on the value of the gender field. I can echo the that back and it looks fine. However, when I put that into an IF statement, I get a parse error

"Parse error: syntax error, unexpected T_IS_EQUAL in....line 9."

What's wrong with my syntax? THANKS!

1 $result = mysql_query("SELECT * FROM teamdata");
2 if (!$result) {
3 echo("<p>Error performing query: " . mysql_error() . "</p>");
4 exit();
5 }
6
7 while ($row = mysql_fetch_array($result)) {
8
9 if ($row['gender']) == 'b' {
10 $gender = 'Boys';
11 } else {
12 $gender = 'Girls';
13 }

[Receptional Andy]

Line 9 appears to have the closing bracket in the wrong place:

if ($row['gender']) == 'b' {

to

if ($row['gender'] == 'b') {

[Little_G]

Hi,

You have a close bracket missing at the end of your if statement on line 9.

Andrew

[edit]We're quick here aren't we![/edit]

[edited by: Little_G at 10:31 am (utc) on Sep. 14, 2007]

[Sandd]

Never mind. Stupid mistake of mine, need to move the ) to the other side. Doh!

[Sandd]

Didn't see your post replies before my 2nd.

THANK YOU!

[g1smd]

I find with these sort of errors that you can stare at them all day and not see the typo, but if you do something else and then come back to it the next day it suddenly becomes very obvious what the problem is... usually.