Trying to get in array working

[Simone100]

Hello, anyone know why this code isn't working? All it shows on the page is the current second but no files on page refresh. Please let me know whats wrong, thanks very much.

<?php
ini_set('error_reporting', 8191);
ini_set('display_startup_errors', 1);
ini_set('display_errors', 1);
$currentfile = date('s');
$allfiles = array();
$allfiles[1] = "thisfile.txt";
$allfiles[2] = "thatfile.html";
$allfiles[3] = "thatfile.gif";
$allfiles[4] = "thisfile.txt";
$allfiles[5] = "thatfile.html";
$allfiles[6] = "thatfile.gif";
if (in_array(".gif",$allfiles))
{echo '<img src="'.$allfiles[$currentfile].'">';}
else {$get_content = file_get_contents($allfiles[$currentfile]);
echo $get_content;}
?>

[dreamcatcher]

Hi Simone100,

This is your problem:

if (in_array(".gif",$allfiles))

Its looking for a value of '.gif' and there isn`t one.

dc

[Simone100]

Thank you very much, I get the same result even if I put in the whole address "thatfile.gif" Is there an easy way to scan for a .gif without all the hassle of preg match?

[edited by: Simone100 at 7:12 am (utc) on Aug. 24, 2007]

[vincevincevince]

I'd recommend using something like strpos() rather than in_array()

[Simone100]

Thanks, it says it will only look for the first position gif, I need it to look for it anywhere in the array.

[vincevincevince]

Then combine it with foreach and test each member of the array individually with strpos

[Simone100]

I don't know how.

Maybe someone can tell me why this one won't work then. Says undefined index on these two lines.
if (in_array(substr($allfiles[$currentfile], -3), array('gif','jpg','png')))
else { $get_content = file_get_contents($allfiles[$currentfile]);

and whole code.

<?php
ini_set('error_reporting', 8191);
ini_set('display_startup_errors', 1);
ini_set('display_errors', 1);
$currentfile = date('s');
$allfiles = Array();
$allfiles[1] = "thisfile.txt";
$allfiles[2] = "thatfile.html";
$allfiles[3] = "thatfile.gif";
$allfiles[4] = "thisfile.txt";
$allfiles[5] = "thatfile.html";
$allfiles[6] = "thatfile.gif";
if (in_array(substr($allfiles[$currentfile], -3), array('gif','jpg','png')))
echo '<img src="'.$allfiles[$currentfile].'">';
else { $get_content = file_get_contents($allfiles[$currentfile]);
echo $get_content;}
?>

Can anyone see why this isn't working? Thanks.

[1][edited by: Simone100 at 9:03 am (utc) on Aug. 24, 2007]

[dreamcatcher]

Hi Simone100,

Try something like this:

$images = array('.gif','.jpg','.png);

foreach ($allfiles AS $file)
{

if (in_array(strrchr(strtolower($file),'.'),$images))
{
echo '<img src="'.$file.'">';
}
else
{
echo file_get_contents($file);
}

}

Not tested, but should work how you want I think.

dc

[Simone100]

Thanks for helping, don't understand this, it says Parse error: parse error, unexpected T_STRING, expecting ')' in
echo '<img src="'.$file.'">';

I tried adjusting the quotations but fouled it up worse and I don't understand why it wants a paranthesis there, seems like the brackets like you have it should be the way.

[edited by: Simone100 at 7:46 am (utc) on Aug. 30, 2007]

[Simone100]

Nevermind, going to try something else. Thanks

[edited by: Simone100 at 8:57 pm (utc) on Aug. 30, 2007]

[cmarshall]

I would HIGHLY recommend using preg_match for this.

preg_match is your friend. He's a bit loopy, but very rich, and will let you drive his Maserati if you learn his lingo.