Calling javascript within php

what's the best way to do this?

[skipfactor]

I'm using the Google Maps API on a dynamic detail page. I want to serve one block of js based upon a database value, else serve a different block of javascript:

$foo=$row_table['col_name'];
if ($foo == 'blue')
{
echo '<script type=\"text/javascript\">
<!--

//-->
</script>';
}
else
echo '<script type=\"text/javascript\">
<!--

//-->
</script>';
?>

What's the best way to do this with a boatload of advanced API code that needs the database?

[smatts9]

You can just stop the script or something of that nature like this:

<?
$foo=$row_table['col_name'];
if ($foo == 'blue')
{
?>

<script type="text/javascript">
<!--
//-->
</script>

<?
} else {
?>

<script type="text/javascript">
<!--
//-->
</script>

<? }?>

Something like that should work.

[skipfactor]

It's amazing what a few question marks can do for a guy's day. Thanks so much.

[mojomike]

thanks to this post I have learned something.

I am just wondering what the ELSE section was for

Mike

[coopster]

I want to serve one block of js based upon a database value, else serve a different block of javascript:

I think the empty blocks are just being shown for example, mojomike.

BTW, PHP calls this Advanced escaping [php.net].

[pixeltierra]

If you have a lot of javascript, you could put it in separate files and include the one you want

if (X) {
include (jsfile.js);
}else{
include (theotherfile.js);
}

Seems cleaner

[skipfactor]

Yes, I did that thanks, but for my situation I had to stuff the js in a php file:

if (X) {
include (jsfile.php);
}else{
include (theotherjsfile.php);
}