HTML below PHP code

Hi, can anyone help, I'm sure it is quite a simple solution (I hope). I have the code below in a file called menu.php it links to a csv file and displays the contents. The only problem I have is that is is not displaying the html code below the php stuff. e.g.

This is the menu page
 
test test test

What am I doing wrong? Do I have to put it all in echo statements?

Cheers

themoron :@)

This is the menu page 

<?php
echo "<center>";
/*/-------------------------------------------------------------------\
Ś Original Name : csvview.php Ś
Ś Author : Neil Maskell Ś
Ś Function : Reads a specified CSV file (Comma seperated) and Ś
Ś converts it into a readable HTML table. Ś
Ś Ś
Ś You could set up a html form with an input field Ś
Ś called filename. Then use csvview.php as the action. Ś
Ś Ś
Ś the reason cache is being disabled is because if you Ś
Ś update the csv file the cache doesnt realise and showsŚ
Ś an older version of the information. Ś
Ś Ś
Ś The CSV files should (and normally are) in the format:Ś
Ś field1,field2,filed3,filed4 Ś
Ś field1,field2,field3,field4 Ś
\-------------------------------------------------------------------/

*/
//
$filename = "menu.csv"; // File to open. quote out this variable if you are using a form to link to this script.
function viewlog($filename) {
$fp = fopen($filename,"r");
$file = fread($fp,65535);
$replaced = eregi_replace(",", "<td>", $file);
$replaced2 = eregi_replace("\n", "<tr><td>", $replaced);
$replaced3 = eregi_replace("\r", "<tr><td>", $replaced2);
fclose($fp);

return $replaced3;
}

// Start the table definition of your choice
echo "<table border=0 bordercolor=black cellspacing=0 align=center cellpadding=0 width=30% style='font-size:12pt'>";
echo viewlog($filename);
echo "</table>";
echo "</center>";
echo " ";
exit;
?>

 
 
This is the menu page

test test test
</body></html>

HTML below PHP code

themoron

jaski

themoron

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