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Toggle an image when checkbox is checked/unchecked

10:57 am on May 17, 2010 (gmt 0)

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joined:Nov 9, 2009
posts: 43
votes: 0

I have six checkboxes in my form. When each one is checked/unchecked I'd like to toggle an image related to that checkbox. Basically, I need the effect that would be achieved by using "oncheck" and "onuncheck" events (would be nice if those existed!) to make the images hidden and visible.

For each of the six checkboxes, I'm currently using "onfocus" and "onblur" events to toggle each image:

<input type="checkbox" onfocus="document.getElementById('[i]myImageId[/i]').style.visibility='hidden';" onblur="document.getElementById('[i]myImageId[/i]').style.visibility='visible';">

But of course the image becomes visible again with the "onblur" event, even if the box is still checked. And of course if I exclude the "onblur" event then it does not toggle back to the original image when the box is checked and then unchecked. Either way, not exactly what I'm going for.

Any suggestions?
12:44 pm on May 17, 2010 (gmt 0)

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WebmasterWorld Senior Member 5+ Year Member

joined:Dec 13, 2009
votes: 0

Try writing a function to toggle it based on a variable, maybe something like:
var x = 1;
function toggleimage() {
if(x == 1) {
x = 2;
} else {
x = 1;
And then the checkbox looks like:

<input type="checkbox" onchange="toggleimage()">

Could even modify that to use the same function to toggle multiple images, although that'll get a bit more complicated:

<input type="checkbox" onchange="toggleimage('imageID')">
var x = new Array();
function toggleimage(theid) {
if(!x[theid]) {
x[theid] = 1;
if(x[theid] == 1) {
x[theid] = 2;
} else {
x[theid] = 1;
12:50 pm on May 17, 2010 (gmt 0)

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WebmasterWorld Senior Member 10+ Year Member

joined:Nov 3, 2005
votes: 0

<input type="checkbox" onclick="document.getElementById('myImageId').style.visibility=(this.checked)?'hidden':'visible';" >
5:58 pm on May 17, 2010 (gmt 0)

Senior Member

WebmasterWorld Senior Member rocknbil is a WebmasterWorld Top Contributor of All Time 10+ Year Member

joined:Nov 28, 2004
votes: 0

Remember that hidden and visible will still take up space in your document, you may want to use the display property, setting it to none to hide, block to display, instead.

If you don't mind it taking up the space, just set the src of the image element. Tested example.

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01
Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html lang="en">
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Swap image</title>
<script type="text/javascript">
window.onload=function() { attachBehaviors(); }
function attachBehaviors() {
// only doing one here, but you can add others
if (
document.getElementById('toggle_chk') &&
) {
// So JS is "aware" of the element style
// Attach the behavior
document.getElementById('toggle_chk').onclick=function() {
function toggle_image(chk) {
// already checked for my_img
// if you want to hide it . . .
// if you just want to swap src
//var src=(chk.checked)?'my_image.jpg':'';
<form action="">
<p><input type="checkbox" name="toggle_chk" id="toggle_chk" value="1" checked>
<label for="toggle_chk">Image on/off</label></p>
<p><img src="my_image.jpg" id="my_img"></p>
5:55 am on May 18, 2010 (gmt 0)

Junior Member

5+ Year Member

joined:Nov 9, 2009
posts: 43
votes: 0

It turns out that daveVk's works great and is a much simpler solution than I expected! And since I don't need to worry about taking up space for what I'm doing, it will be perfect.

Much obliged to you all for your suggestions!

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