Forum Moderators: Robert Charlton & goodroi
ajaxCall("http://example.com/dynamicWidgetCode.html")
So now the above url, which only shows a portion of the page, without css, is in the google index and outperforming the parent page for some reason.
So how would you all go about fixing this problem? First, I need google to not index this page... I guess I can assemble the url from parts when I make the call. Then, I guess I will stick a javascript snippet that does a redirect to the real page...
But what do I do about the fact that the page is already in the Google SERPS? I want the parent page, not this UI element....
Thanks,
Jim
[edited by: Robert_Charlton at 7:42 pm (utc) on Jan. 15, 2008]
[edit reason] use example.com - it can never be owned [/edit]
Oh and stop using .html for anything that you don't want indexed. Or use robots.txt or other means to ensure that they don't get indexed in the future.
[edited by: LoganFoster at 1:33 am (utc) on Jan. 16, 2008]
1) Renamed the Ajax widget page
2) Robot.txt dissallow for new and old ajax widget pages
3) 301 redirect from old ajax widget page to the parent page.
My parent page started showing on the first page of Google SERPS within 8 hours.
Thanks Again,
Jim