two variables in an if(!$var1$var2)

[omoutop]

Hi to all!

I have this code:

1--<? $Querytype = "select * from Type";
2--$resulttype = mysql_query($Querytype);
3--$timestype = mysql_num_rows($resulttype);
4--$i = 1;
5--while ($rowtype = mysql_fetch_assoc($resulttype)
6--AND $i <= $timestype)
7--{
8--$type1 = $rowtype ['type'];
9--echo $type1;
10--if (!type$i)
11--{?>
12--<input type="checkbox" name="type<? echo $i?>"
13--value="<? echo $type1?>">
14--<? }
15--else
16--{
17--?>
18--<input type="checkbox" name="type<? echo $i?>"
19--value="<? echo $type1?>" checked>
20--<?
21--}
22--$i++;
23--};

In line 10 i have an if statement containing this:
if (!type$i) which is not working....
because itshould be like this:
if (!$type$i) which is also not working...

HOW CAN I HAVE TWO VARIABLES as one string within my if () statement?!
PLZ HELP ME

[grandpa]

Try this:

if (!type AND !$i)

[webvand]

Agreed with grandpa,

for a mixing if std. you can use "AND" (or "&&" instead). Also "OR" (or "¦¦" instead) for OR operation.

if ($a == "1" && $b == "1") echo "Both of them = 1";
if ($a == "1" ¦¦ $b == "1") echo "One OR Both of them = 1";

[dreamcatcher]

For more info see:

[uk2.php.net...]

[dcrombie]

if(!${"type$i"}) { 
 // do stuff 
}

;)

[omoutop]

Thx everybody for your replies!

dcrombie u r so right..IT WORKED!
U RULE!
THX MAN!