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Supplied argument is not a valid MySQL result resource
in my PHP pages..the thing is I am following a tutorial line by line. ¦ did a search and found other web pages with this very same thing check out. > [dearones.com...]
Now surely all these people would realise they have a problem? Is it because there is something missing from the PHP installation?
Its really starting to do my head in.
An SQL query looks like so
SELECT * FROM table_name WHERE table_id = 68;
And table structure means what was used to make the table you are calling in your query. For example:
CREATE TABLE pet (
That was taken from the mysql website manual [mysql.com]
Hope this helps some.
[added]I could be misinterpreting what GrodanBoll meant by saying table structure. [/added]