How to check if an array element has a value?

[irock]

Hi, whenever I tried to use a simple IF statement (if $items[0]['store-offer_store-name'] == "") to check if the variable has a value, it doesn't quite work.

I think I'm approaching ths problem the wrong way. Is there some sort of function I can check to see if $items[0]['store-offer_store-name'] actually has a value?

Also when I tried to print out $items[0]['store-offer_store-name'], I got something like this...

Array['store-offer_store-name']

Thanks for any help.

[jatar_k]

have you tried

if ($items[0]['store-offer_store-name'] == "" ¦¦!isset($items[0]['store-offer_store-name']))

that echo looks funny though

how are you setting it?

[jamie]

jatar_k

i don't think you need to do any!isset() or == "" to check the value of any variable, including part of an array.

if the value of the $var is 0, empty, NULL or FALSE, it returns a false value, otherwise it returns true,

so the simple statement if ($var) or if (!$var) is enough without all the isset, etc

re: irock's array, it looks like there is something wrong with the array itself as opposed to the checking?

[coopster]

irock, use the print_r function to print out your arrays (works on all arrays, including multi-dimensional). Using the <pre> tags will print it out nicer:

<?php 
print '<pre>'; 
print_r($items); 
print '</pre>'; 
?> 

This should show you your values.

[jatar_k]

$var is 0, empty, NULL or FALSE,

true but I usually test each individually as each of those cases could denote a different behaviour.