Forum Moderators: coopster
/exit.php?url=www.site.com
However, when the other site has parameters that I also need to include, the script stops working. For instance:
/exit.php?url=www.site.com?other_site_paramenter=test
I know the problem is the 2 question marks... but I can't find a list of codes for the replacement value. In the late 90s I knew this... the? and & characters should resolve to something with %, but I can't remember what. Can anyone help out?
Thanks in advance :)
-Julia
Passing an argument with & in the URL [webmasterworld.com]
This thread might be the answer. If not, just ask away.
I think that by replacing? with %3F and & with %26, etc. - the 2nd URL should resolve properly. Those are the codes I was looking for.
Thanks again,
-Julia