variable inside a regular expression

[Anguz]

how do I use a variable inside a regular expression in php?

thank you in advance

[liketoseeyoutry]

Try this ...

$regex = "<match>".$variable."<more stuff to match>";
ereg($regex, $string, $regs);

[vincevincevince]

There is no problem with using variables within regular expressions. Either conc them together with . i.e. "/reg-".$var."-exp/" or just include them straight away "/reg-$var-exp/"

[MonkeeSage]

my $blah = "33";
my $foo = "blah33blah44";
if ($foo =~ s/\Q$blah/22/g) {
print $foo;
}

Jordan

[daisho]

MonkeeSage does that work in PHP? Since when? That looks like perl to me. I though you had to use preg_* functions in PHP for regex?

daisho.

[jatar_k]

yes you do
"=~" == perl

I am sure that is an oops ;)

[Anguz]

I see

I have seen =~ in a php script once before, what does that mean?

[daisho]

Unlikely Anguz unless it was in quotes which meant it didn't mean anything to PHP.

A quick look at the PHP Parser Tokens [php.net] shows that tilde "~" is not one.

daisho.