shell_exec and variables

[tekomp]

I'm trying to execute a shell command within a loop to fetch a filename that is stored in an array, but it's not substituting the array with the contents of the array. Here's what I have:

for($i; $i<count($matches[1]); $i++)
{
  `/usr/bin/fetch $matches[1][$i]`;
}

Outputs:

fetch: Array[0]: No such file or directory
fetch: Array[1]: No such file or directory

In this case, there are two files in the array, so I would need the script to fetch the files in $matches[1][0] and $matches[1][1].

Any ideas?

Thanks.

[coopster]

Have you tried dumping that variable to the browser first to be sure it is structured and contains what you think should be there, a string value representing a filename?

print '<pre>'; print_r($matches); print '</pre>'; exit; 
for($i; $i<count($matches[1]); $i++) 
{ 
`/usr/bin/fetch $matches[1][$i]`; 
}