Welcome to WebmasterWorld Guest from 188.8.131.52
my arithmetic gives 144 as the answer. ;)
Four runners with short, easy to remember, monosyllabic
names have 24 possible finishing orders if they decide to
compete against each other in a race.
If they are unsatisfied with the result of the first race
and decide to do it again, then another 24 possible
finishing orders can be added to this total.
These four guys, though, are devoid of sensibility and
continue this idiotic pursuit a further four times, which
adds up to 144 possible finishing orders by my reckoning.
My arithmetic, of course, may be totally wrong, as I am...
If Usain Bolt was foolish enough to run in a race with members
of the alphabet and assuming that he would arrive in first place
over all distances, then there would be just 6 outcomes for
- Usain Bolt, b, c, d
- Usain Bolt, b, d, c
- Usain Bolt, c, b, d
- Usain Bolt, c, d, b
- Usain Bolt, d, b, c
- Usain Bolt, d, c, b
I feel sure that the alphabeters would realise that resistance was
futile and end proceedings at that juncture. ;)
Whats the answer ?