Context node:
<a>
<c refid="1" />
<c refid="2" />
<c refid="3" />
<c refid="4" />
<c refid="5" />
</a>
It gets the nodes referred to above, using a proprietary command:
<xsl:for-each select="get-a(@refid)">
<a id="1">
<f att1="C"/>
<f att2="I"/>
</a>
<a id="2">
<f att1="C"/>
<f att2="I"/>
</a>
<a id="3">
<!--doesn't have f att1-->
<f att2="I"/>
</a>
<a id="4">
<f att1="R"/>
<f att2="S"/>
</a>
<a id="5">
<f att1="G"/>
<f att2="I"/>
</a>
At present, I have it call a template within a for-each, but that will only do each node separately, obviously. But it must process them first based on the att2 value (these are set values, always I or S, so no problem), and then within that, based on att1 value to produce something like below, the first P node being the problem:
<O>
<P d="C" e="I"> <!-- This C is not a set value but a string, and it could be anything. Once the nodes with the same attribute are isolated, it is fine to grab the att value from node in position 1-->
<id1>
<!-- other info via call template; this works -->
</id1>
<id2>
<!-- other info via call template; this works -->
</id2>
</P>
<P d="NULL" e="I">
<id3>
<!-- other info via call template; this works -->
</id3>
</P>
<P d="G" e="I">
<id5>
<!-- other info via call template; this works -->
</id5>
</P>
<P d="R" e="S">
<id4>
<!-- other info via call template; this works -->
</id4>
</P>
</O>
I have tried for-each-group calling a different template, and for-each with a sort for the value of att1, and other methods with no success. This gives the right order, but I cannot bring nodes with same C value together:
<xsl:sort select="a/f/@att2"/>
<xsl:sort select="a/f/@att1"/>
The logic should be
for each <a> with same att2 value
for each <a> with same att1 value
output a single P with d=att1 value
then process nodes with same att1
I know XSLT can't "loop" the way I'm used to with Perl, but I feel there is some way to do this by grouping or sorting, I just can't find the right combination. I keep getting so close, but then can't complete it. Many thanks in advance.
