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JavaScript and PHP help

5:23 pm on Jun 11, 2008 (gmt 0)

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WebmasterWorld Senior Member 5+ Year Member

joined:June 10, 2008
votes: 0

I need to display multiple lines with JavaScript and PHP here is my code.
Header("content-type: application/x-javascript");

//displays an alert box with a php varible $msg passed into it
function echoAlert($msg){

echo "alert('$msg')";


$var = ("File Written to Sybase01\\\insurance$\\\MSBCBS\\\Send Log\\\Sending\\nContents:");

//$lines is an array of a multiple line text file
foreach($lines as $i){

//function to be used later
//writeLog($username, $i);
$var .=("\\n {$i}");


This code is executed by another javascript file when the user clicks a button. The problem is my alert box says error missing ")" after argument list. If I manually store multiple lines of var i.e.
$var .= ("\\n {$text1}");
$var .= ("\\n {$text2}");
The alert box works fine.
As I am not a Javascript person, I believe it either has something to do with the way the variable is stored in the array or my escape characters. Any suggestions, thanks in advance.

2:27 pm on June 12, 2008 (gmt 0)

Senior Member

WebmasterWorld Senior Member korkus2000 is a WebmasterWorld Top Contributor of All Time 10+ Year Member

joined:Mar 20, 2002
votes: 0

It could possibly be what is in the array. Try looking at whats in the array and see if it has any characters that need to be escaped. Other than that I am not sure why it is working one way and not the other.
9:50 pm on June 13, 2008 (gmt 0)

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WebmasterWorld Senior Member 10+ Year Member

joined:Apr 20, 2004
votes: 0

I'm not a big fan of trying to execute a client-side action with a server-side language, so I've broken your script up into server- and client-side sections:

<script type="text/javascript">
function echoAlert(msg){
$var = ("File Written to Sybase01\\\insurance$\\\MSBCBS\\\Send Log\\\Sending\\nContents:");
foreach($lines as $i){
$var .=("\\n {$i}");
<script type="text/javascript">
echoAlert('<?php echo $var?>');

This works fine. Your original code did nothing except print out "echo ('File written.." for me.

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