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Math Geek Christmas Card: Who get's this?

I didn't...

     
3:04 pm on Dec 1, 2004 (gmt 0)

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3:06 pm on Dec 1, 2004 (gmt 0)

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Let's put a spoiler buffer
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So we don't ruin it for the rest.
3:28 pm on Dec 1, 2004 (gmt 0)

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I get it, but there's a misspelling.
8:06 pm on Dec 1, 2004 (gmt 0)

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Yes, there is a spelling mistake, but I have used it to design an I.S. department card. Most of the rest of the company are engineers. I'll be interested to see if they notice it.
5:59 am on Dec 2, 2004 (gmt 0)

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I get it in theory, but without the knowledge necessary to really get it. I love FoxTrot. His strips are s-m-r-t.
10:44 am on Dec 2, 2004 (gmt 0)

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Clue #1. E = 2.71828
11:43 am on Dec 2, 2004 (gmt 0)

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I guess clue #2 is "H20"?

I have no idea what it is. The log scale indicates it might have something to do with the speed that water turns to snow or something like that?

3:58 pm on Dec 2, 2004 (gmt 0)

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I think the H2O stuff is a red herring. It threw me off. I would ignore it and just focus on the equation.
4:14 pm on Dec 2, 2004 (gmt 0)

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I'm no mathematician though - perhaps someone could explain it for my benefit as it's got my curiosity now!

Perhaps sticky me if you don't want to spoil it for others...

Thanks!

TJ

4:59 pm on Dec 2, 2004 (gmt 0)

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SPOILER!
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M is M
2.718 is the base of natural logarithms known as e
r squared is rr
the inverse of 1/y is y

or "merry"

the square root of x is just x
force divided by acceleration is mass

or "xmass"

Merry xmass

6:24 pm on Dec 2, 2004 (gmt 0)

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Congratulations, atadams! I've been thinking about this since the thread started - I thought it was some kind of equation for snow/water, with force/acceleration of snowballs of something... I was going to do some math searching just to find it, at least I've been saved that. ;)
9:07 pm on Dec 2, 2004 (gmt 0)

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I thought it was some kind of equation for snow/water, with force/acceleration of snowballs of something

My (incorrect) thoughts also!

Thanks & well done!

TJ

9:25 pm on Dec 2, 2004 (gmt 0)

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Just to clairify. I didn't get it myself. A PhD here at work figured it out.

;)

11:23 pm on Dec 2, 2004 (gmt 0)

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Shouldn't need a Ph D unless standards have slipped. I dropped out of an engineering course in 1970. Undergradute physics should be enough.
2:18 am on Dec 3, 2004 (gmt 0)

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I don't think he needed it, but he had it anyway!

:)

2:23 am on Dec 3, 2004 (gmt 0)

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Post hole digger?
4:31 am on Dec 3, 2004 (gmt 0)

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I got this pretty easy and all I have is a HS diploma.

I got it pretty quickly. I think most people are trying to look too deep into it. As with anything....the simplest solutions is usually the right one.

6:54 am on Dec 3, 2004 (gmt 0)

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Well, I guess I didn't have it. I only had the obvious part. I knew I should've bothered to take physics before I dropped out of college. Abnormal Psych, what did that get me? Certainly not the understanding of smartly done comics.
2:02 pm on Dec 3, 2004 (gmt 0)

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> Undergradute physics should be enough.

Yeah, well I took my undergraduate physics in 1989, so it's a wee bit rusty. I looked at this comic and thought, "Ugh. I'm sure it's funny, but I have no time for this anymore."

hee.

Thanks for the interpretation, though!

3:06 pm on Dec 3, 2004 (gmt 0)

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Whoooooosh!

sound of quip passing very quickly overhead - I do draw pictures for a living

3:09 pm on Dec 3, 2004 (gmt 0)

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I got it after the E = 2.71828 hint.

Foxtrot is a great cartoon.

4:20 pm on Dec 3, 2004 (gmt 0)

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My degree was in political science (1981), but I did take some physics and chemistry (don't remember much).

I got the e part, but the H2O part threw me off. I thought it something about the rate at which water freezes or becomes snow.