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Does it make any difference if you were to leave it as one single page or if you were to add 10 pages of content and link back each page to the index page? Meaning does the PR of the index page increase simply by having 10 internal links now pointing back to the index page? Or does it not increase the index page's PR but now you have 10 pages with some PR that you can use to link to other sites/pages?
thanks
BTW - is there a certain time of day that the update happens at?
Read through to the second page from the start.
I made several long posts elaborating on the difference of website and webpage as in regards to PR.
In short. Every page has PR to give away. If they give it to your index page (no matter where they are) it'll help.
Let me phrase this another way. If you take a brand new domain and you link two pr6 sites to that index page it will have x PR.
If you take the same domain and link the same 2 pr6 sites to the index page but you add 10 pages that link back to the index page - will the index page have a higher PR than the first case?
[webmasterworld.com...]
In fac they will boost teh most if the index page links to each one, giving them a tenth of its PR.
So lets say the two PR 6 links give the index page a PR of X. Then each of the 10 sub pages gets it's own PR 1 (dampened) plus 1/10th of the PR x of the index page. lets call these PR y sinc e they should be equal. So then we link each back to the home page. taht gives the home page 1/1 or PR y *10 additi0onally to PR x, which of course again increases the PR it gives to these subpages. through all iterations.
Ultimately any page linking in adds PR. And the best page to link to you is the one you jsut linked to and that ONLy link to you back. (and it if gets other incoming links like in your PR 6 example then even better)
could somebody please post a link to te official paper by Google regeardign the PR formula? (I don't have it handy)
If you add N pages, each has one incoming link from the index page and backlinks just to the index page, then
- the PR of the index page is X/(1-d^2) + (d*N+1)/(1+d)
- the total sum of PR on your site is X/(1-d)+N+1
where d is the damping factor (wich is probably 0.85) and X denotes the incoming PR. Of course, PR is the real PR and not ToolbarPR which are correlated by a log scale.
If you have only an index page PR is only X+(1-d).
One can see that (if the incoming PR is relativ high) the main effect is already reached by adding one additional page. Obviously, every page increase the total PR of the site by one.
But no more than the total pr on the site.
You have 10 pages that are empty. PR comes in to the site from inbound links. You can then share the pr among the pages by internal linkage, but you can't create it from scratch - you can only share the wealth. By sharing the wealth, you are increasing your chances of getting referrals because more obscure keyword phrases will now have more pr and hence, a higher ranking. It's always better to have 10 pages that produce 5 referrals a day, than 1 page that produces 50 referrals a day. eg: you want referrals coming in on 50 phrases and not just on one. share the wealth.
After all the external pages submit to the same laws as your own, and by your argument couldn't "create PR from scratch" either.
According to the google papers, each pages has an inherent PR of 1 to give away.
indeed, each additional page - as long as it is not a dead end - increases the total amount of PR by 1. However, the effect for the index page (if these pages are linked in the way described before) is small if there is already a least 1 page backlining to your index page, i.e. PR for the index page is just increased by d/(1+d) for each additional page. This is normally small compared to incoming PR.
However, you need a site with #pages >> 10.000 to get a high PR for at least some of your pages. Here we a talking about "x number of high PR" respectively "2 pr6 sites" and about less than 100 internal pages. In this case the effect (for PR) of more than 2 pages (index + one other page) can be neglected as can be seen from the calculation above (msg# 10).