Pub Con

Any use for beginners

[mcconboye]

I am a complete beginner and was wondering if this Pub Con in London is of any use.

Thanks

[heini]

No I don't think so.
Why, meeting people from all angles of webmastering and promotion, from non- to highly commercial, from absolute beginner to veteran, networking, exchanging ideas, expanding horizons, all that in a most comfortable setting - certainly not a good thing.

[DaveN]

yer I agree with heini, sitting around drinking beer you can ask anything from what is CSS to the complete break down for PR(A) = (1-d) + d(PR(t1)/C(t1) + ... + PR(tn)/C(tn)) and someone will know the answer.

shame it's sold out.

DaveN

[creative craig]

PR(A) = (1-d) + d(PR(t1)/C(t1) + ... + PR(tn)/C(tn))

Have to remembe to ask that before I drink to much ;)

Craig

[mcconboye]

Yeah, I just realised it's sold out.

Thanks anyway

[heini]

>sold out

See you at the next pubcon then!

[DaveN]

craig get this printed on to a tee-shirt.

please explain this to me :
PR(A) = (1-d) + d(PR(t1)/C(t1) + ... + PR(tn)/C(tn))

DaveN

[GodLikeLotus]

I've just seen tickets on Ebay going for $1000 a piece.

[Chndru]

I've just seen tickets on Ebay going for $1000 a piece.

Really? I tried to search to vain :(

[jdMorgan]

> please explain this to me :
> PR(A) = (1-d) + d(PR(t1)/C(t1) + ... + PR(tn)/C(tn))

Ask ciml... But be prepared to have a long discussion over the value of "d".
(And move this thread to the Google forum) :)

Jim

[rcjordan]

>Ask ciml... But be prepared to have a long discussion over the value of "d".

We're still debating over the log base on that one.

[lorax]

>> Have to remembe to ask that before I drink to much

Ack - don't do it in this crowd - you'll get a dope slap for sure (well maybe not but a blank stare followed by a sniggle might occur). Try a search on Google and you'll get your answer. ;)

[creative craig]

Have to remember that lorax ;)