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PHP array key issue



2:50 pm on Jun 10, 2012 (gmt 0)

5+ Year Member

Hi there,

I have the following code accessing values from an associative array:

foreach ($genders[$lang] as $value) {

if($value==true) {

echo key($genders[$lang]);




The key function however only echoes the key name of row 1, it seems to be skipping row 0. The contents of the array are:

Array ( [m] => 1 [f] => 1 [n] => 1 [c] => [mp] => [ma] => [mi] => )

So when I run the above code I get the output "fnc" instead of "mfn". Itís as if the if statement is detecting the correct row but the key function is not.

Iíve tried Googling around this but to no avail, I wonder if any of you guys can help :)



4:18 pm on Jun 11, 2012 (gmt 0)

WebmasterWorld Senior Member rocknbil is a WebmasterWorld Top Contributor of All Time 10+ Year Member

Generally there's no reason to use next in a for/foreach loop, and may have something to do with it. It's not like a "next" in any other languages, it is used to advance the pointer within the loop (instead of just going to the next item.) It advances the pointer by one (one more than it would in a normal for/foreach.)

You don't need to evaluate true/false, 1/0 if your array values could be empty or null. It is, or it is not, allowing you to try a more simple method:

foreach ($genders[$lang] as $value) {
if($value) {
echo key($genders[$lang]);


8:43 pm on Jun 11, 2012 (gmt 0)

The use of
is what's messing things up. The
loop automatically advances to the next element in the array, so there's no need for you to do it "manually".

Note: It's best to be as explicit as possible. Yes,
if( $value == true )
if( $value )
will work if
, or
, but it will also "work" if
. That's probably not a good thing.

if( $value == true )
should be
if( $value === 1 )
is an actual integer) or, even better,
if( 1 === $value )
. Getting into the habit of placing the variable on the right means that you avoid this sort of "whoops!" moment:
if( $value = 1 )


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