Forum Moderators: coopster
mysql:
$result2 = mssql_query("select * from users where userID = ".$globalID);
mssql:
Warning: mssql_query() [function.mssql-query]: message: Incorrect syntax near '='. (severity 15)..
whats wrong with this syntax?
$result = mssql_query("select FirstName,LastName from users where userID =" .$globalID );
$result = mysql_query("select * from students order by LastName asc limit ".$globalOffset.", 20");
correct..
mssql:
$result = mssql_query("select top 20 * from files order by DocTitle asc = ".$globalOffset);
error
Warning: mssql_query() [function.mssql-query]: message: Incorrect syntax near '='. (severity 15) in
==============================================
what wrong with this statement?
$result = mssqL_query("select * top 20 from files where DocTitle = ". $globalOffset);
This does not look quite right to me. Presumably DocTitle is a string/varchar field and its value needs to be quoted in the SQL (MySQL or MSSQL)....?
ie.
$result = mssql_query("select top 20 * from files where DocTitle = '". $globalOffset."'");
$result = mssql_query("SELECT top 20 * FROM files WHERE m_folderid = '".$globalOffset."' ORDER BY DocTitle ASC");
i tried dis dis script but there is an error
$result = mssql_query("SELECT top 20 * FROM files m_folderid = '".$globalOffset."' ORDER BY DocTitle ASC");
======================================================
dis is my script
if (isset($_GET["page"]))
{
$globalOffset = $_GET["page"];
$globalOffset = preg_replace( '/[^0-9]/', '', $globalOffset);
}
else
{
$globalOffset = 0;
}
[edited by: eelixduppy at 6:27 am (utc) on May 8, 2009]
[edit reason] no URLs, please [/edit]