Unix Shell Script

[helpline]

Hi,

I want to write a Shell Script in the Unix....So please help me

Convert a number into binary by using the Shell Script.

Thanks.

[moltar]

Which shell are you using?

[helpline]

I am using the "Bourne Shell" and "vi" editor.

Suppose shell script name is : convbinary

$vi convbinary

---
--
-----

---

Esc : wq

sh convbinary.

Thanks.

[moltar]

What do you need help with?

[helpline]

Basically this is a program to convert a number into binary format. I have written that in C language.

/* Program to convert a number into binary */

#include<stdio.h>
#include<conio.h>
void main()
{
int num,i,j,k;
int number[10]; /* let num be an array of integer */
k=0;
clrscr();
printf("Enter a Number : ");
scanf("%d",&num);

while(num>0)
{
j=num%2;
num=num/2;
number[k++]=j;
}

printf("Binary Format : ");
for(;k>=1;k--)
printf("%d",number[k-1]);
getch();
}

Suppose the user input is 12, It will display in the binary is : 1100

Thanks.

[moltar]

#!/bin/bash2 
  
declare -i num=$1 
declare -i j=0 
declare -i i=1 
declare -a bin=() 
  
while (( num > 0 )) 
do 
  let j=$num%2 
  let num=$num/2 
  let bin[i]=(${bin[$i]}$j) 
  let i=$i+1 
done 
  
while (( i > 0 )) 
do 
  echo -n ${bin[i]} 
  let i=$i-1 
done