I have an issue that is driving me crazy. I have a xml document and associated stylesheet. I simply want to be able to 1: declare a top level variable 2. Pass a variable value from the URL to the stylesheet so that, for example, if [someurl.com...] - the information for the 3rd ID is displayed. Below i have sample code but i can't seem to get this to work with Php 5. Does anyone have a clue as to what is going on. After spending about a week looking through the documents for Php5 and XML, I am totally confused. Note: I am looking for the simplest / most direct solution.
// XML string
$xml = '<?xml version="1.0"?>
// XSL string
$xsl = '
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="ISO-8859-1" indent="no"
My PHP variable : <xsl:value-of select="$myvar"/><br />
My node set : <xsl:value-of select="$mynode"/>
$xh = xslt_create();
// the second parameter will be interpreted as a string
$parameters = array (
'myvar' => 'test',
'mynode' => '<foo>bar</foo>'
$arguments = array (
'/_xml' => $xml,
'/_xsl' => $xsl
echo xslt_process($xh, 'arg:/_xml', 'arg:/_xsl',NULL, $arguments, $parameters);