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---- MySQL LIKE code not working in safari browser


lostdreamer - 9:25 am on Sep 12, 2012 (gmt 0)


How are you giving the query the $search variable?

When you say that you first get the correct list, but in safari it will then refresh and show all rows, I'm thinking you're using javascript (ajax call?) or something?

If this is the case, it could very well be that it first gives the right $search variable, but than (for some reason) it does another call without the $search variable, thus returning all rows.


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