Msg#: 4482012 posted 5:30 pm on Aug 5, 2012 (gmt 0)
Hi i have a string with this type content: " 2012-02-12 my name is Smith . 2020-11-05 hello world 1234678... " i want to get all dates and replace thats with other string. i need regular expression for fetch dates. please help me
Msg#: 4482012 posted 6:07 pm on Aug 5, 2012 (gmt 0)
$string = ' John Smith birth date : 1989-02-11 Joe Smith birth date : 1991-09-10 Kitty Smith birth date : 1977-12-01 Lora Smith birth date : 1984-05-25 Josef Smith birth date : 1995-02-14 '; ////Simulated Codes in string foreach $birthdate as $date $unixtime = strtotime(date); replcae(date ,$unixtime ) endforeach
Msg#: 4482012 posted 10:07 pm on Aug 5, 2012 (gmt 0)
Seems like overkill. Do you have code at an earlier stage that forces dates into the form you've shown, yyyy-mm-dd ? If so you should be able to just tweak that code and work backward.
Picking up the yyyy-mm-dd piece as a raw Regular Expression, independent of content,* is so trivial that I'm not going to insult your intelligence by writing it out.So I assume you're really asking something a little more complicated ;)
* That is, if you don't care whether the person claims to have been born on 2012-08-05 or 1776-02-31 or even 2555-55-55. If the first-round code was careful, the third form will definitely never occur, probably not the second and maybe not the first.