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How can i display output from dynamically generated variables
Nani22



 
Msg#: 4423493 posted 9:00 am on Mar 1, 2012 (gmt 0)

for($i=1;$i<=5;$i++)
{
$previous_dsgn_{$i}=$_POST["previous_dsgn_$i"];
$previous_place_{$i}=$_POST["previous_place_$i"];
$previous_year_{$i}=$_POST["previous_year_$i"];
$previous_dsgn_{$i}="$previous_dsgn_$i";
$previous_place_{$i}="$previous_place_$i";
$previous_year_{$i}="$previous_year_$i";
}
echo "$previous_dsgn_$i,$previous_place_$i,$previous_year_$i";

guys i am getting output array6,array6,array6 instaed of entered details,how can i get output that i entered

 

incrediBILL

WebmasterWorld Administrator incredibill us a WebmasterWorld Top Contributor of All Time 5+ Year Member Top Contributors Of The Month



 
Msg#: 4423493 posted 1:05 am on Mar 2, 2012 (gmt 0)

Try defining the vars like this:

${"previous_dsgn_{$i}"} = "this is a test for var $i";

eelixduppy

WebmasterWorld Senior Member eelixduppy us a WebmasterWorld Top Contributor of All Time 5+ Year Member



 
Msg#: 4423493 posted 1:10 am on Mar 2, 2012 (gmt 0)

Hi and welcome to webmasterworld!

First off, you should be echoing the variables within the for loop, not outside of it. This still won't help, however, because I believe the syntax for the variable variable would be something along the lines of this:


echo "${previous_dsgn_$i},${previous_place_$i},${previous_year_$i}";


But whenever you use variable variables there has to be a real good reason why you would want to do something like this. So, why are you implementing it like this as oppose to, say, using an array to hold these values?

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