Mahabub
msg:4301136 | 8:40 am on Apr 20, 2011 (gmt 0) |
I hope it will work
$var1=1;
$var2=2;
$var2 = ($var1 == 1 ) ? 4 : $var2;
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mbabuskov
msg:4301207 | 11:42 am on Apr 20, 2011 (gmt 0) |
$var = 1, assigns 1 to $var and returns it (1). Therefore
if ($var = 1)
is the same as:
$var = 1;
if (1)
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jecasc
msg:4301223 | 12:05 pm on Apr 20, 2011 (gmt 0) |
Keep in mind that:
if ($var1=1)
is not the same as
if ($var1==1)
I am not quite sure what you are doing but if I understand it correctly you want:
if ($var1 == 1) $var2 = 4;
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skoff
msg:4301259 | 1:34 pm on Apr 20, 2011 (gmt 0) |
ok so i'll try to be more specific!
i have declared two variables
$var1=rand(0,1);
$var2=rand(0,1);
And what i want to do is
if $var1=0 then $var2 can = 0 or 1
But if $var1=1 $var2 can just = 0
i know it's not really what i explained first but thats what i need to know how to do!
Thanks! ;)
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jecasc
msg:4301262 | 1:37 pm on Apr 20, 2011 (gmt 0) |
$var1=rand(0,1);
if ($var1==0) $var2=rand(0,1);
else $var2=0;
or
$var1=rand(0,1);
$var2=rand(0,1);
if ($var1==1) $var2=0;
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skoff
msg:4301266 | 1:45 pm on Apr 20, 2011 (gmt 0) |
damn! that was fast! :O thanks a lot :D
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