| parse error: syntax error, unexpected T VARIABLE
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alertsfortraders
msg:4183258 | 6:29 pm on Aug 6, 2010 (gmt 0) |
I do not even consider myself a newbie with php, I consider myself to know nothing. I am trying to write a simple piece of code but keep getting an error. here is the error i get:
Parse error: syntax error, unexpected T_VARIABLE in /home/website/www.example.com/wp-content/plugins/exec-php/includes/runtime.php(42) : eval()�d code on line 17
Here is my code:
<?php
$wpusername = $_POST['wpusername'];
$symbol = $_POST['symbol'];
$type = $_POST['type'];
$alert = $_POST['alert'];
$trigger = $_POST['trigger'];
$price = $_POST['price'];
//now we open the file using the a flag, this will create the file if
//it does not exist, and puts the pointer(where it starts writing) at the
//end of the file
$filename = "pricealerts.csv\";
$handle = chmod('/dir/path','0777') fopen($filename, 'b');
//now we prepare our string to be added:
$string_to_add = "$wpusername,$symbol,$type,$alert,$trigger,$price,\n";
fwrite($handle, $string_to_add);
//now close the file
fclose($handle);
?>
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[edited by: dreamcatcher at 5:51 am (utc) on Aug 7, 2010]
[edit reason] exemplified server path [/edit]
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sonjay
msg:4183365 | 10:15 pm on Aug 6, 2010 (gmt 0) |
In this line:
$filename = "pricealerts.csv\";
The backslash is escaping the quotation mark, so php doesn't think that quoted string is closed until it reaches the first quotation mark in this line:
$string_to_add = "$wpusername,$symbol,$type,$alert,$trigger,$price,\n";
At which point, it sees $wpusername as an unexplained variable.
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alertsfortraders
msg:4183486 | 6:53 am on Aug 7, 2010 (gmt 0) |
I removed the \ that you advised me to and got another error.
Parse error: syntax error, unexpected T_STRING on line 14
Here is what it is now
<?php
$wpusername = $_POST['wpusername'];
$symbol = $_POST['symbol'];
$type = $_POST['type'];
$alert = $_POST['alert'];
$trigger = $_POST['trigger'];
$price = $_POST['price'];
//now we open the file using the a flag, this will create the file if
//it does not exist, and puts the pointer(where it starts writing) at the
//end of the file
$filename = "pricealerts.csv";
$handle = chmod('/dir/path','0777') fopen($filename, 'b');
//now we prepare our string to be added:
$string_to_add = "$wpusername,$symbol,$type,$alert,$trigger,$price,\n";
fwrite($handle, $string_to_add);
//now close the file
fclose($handle);
?>
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Matthew1980
msg:4183495 | 8:24 am on Aug 7, 2010 (gmt 0) |
Hi there alertsfortraders,
What are you trying to achieve?
$handle = chmod('/dir/path','0777') fopen($filename, 'b');
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your assigning too much to the 'handle' variable, fopen needs to be on its own line, and preferably setting it's read write directive to 'r+' (read and write) [uk3.php.net ]
And chmod() only needs to be set to 755, I have no idea why people try to give absolute full permissions to directories at all, 755 is plenty - at least that's what I usually do, but that's just my opinion :)
What is the format of the data in the CSV file (I know as it means comma separated, but you never know)
and:-
$string_to_add = $wpusername." ".$symbol." ".$type." ".$alert." ".$trigger." ".$price."\n";
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I'm guessing as you will want spaces between the individual strings? Then again I am guessing..
If this is all in the same directory you will be fine, but I strongly suggest that you learn to define root folders so that you can make access a little more reliable...
Hope I haven't confused you too much.
Cheers,
MRb
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