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PHP Server Side Scripting Forum

Posting a form in a loop

 8:10 am on Oct 29, 2008 (gmt 0)

Im creating a form in a loop and then using get to pass a variable.

The problem is it is posting multiple variables :

while ($row = mysql_fetch_assoc($r)) {


echo "<tr bgcolor=",$bgcolor," ><td width='310' align='center' > Interested </td><td> <form action='book.php' method='get'>";
echo "<input type ='hidden' name='activity' value=",$activityid," />
<input type='submit' name='submit' value='Book Now' /> </td></tr>
"; }

The if you examine my header it looks like this :


which means it is posting all the activities if i am not mistaken ?



 8:49 am on Oct 29, 2008 (gmt 0)

If you intend to only use 1 row from mysql result then put a LIMIT 1 in your query, or remove your while loop. And i think "<form>" and "</form>" should be outside your loop

[edited by: Anyango at 8:50 am (utc) on Oct. 29, 2008]


 3:32 pm on Oct 30, 2008 (gmt 0)

As Anyango already said, if all form fields are going as one form submissions you need to for tags outside the loop. But that may not help the problem at hand. My suggestion is to convert the field names to arrays, for example:

it currently is:
<input type ='hidden' name='activity'

change to :
<input type ='hidden' name='activity[]'

I'd also recommed changing the action to POST - GET is probably not the best option for forms (unless you have a good reason to us it)

However, if you actually do want to have multiple different forms, then just give each form a unique form name tag value.

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