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Not sure how to capture type without a form
php
jonorr




msg:4569912
 6:43 am on May 2, 2013 (gmt 0)

I would like to embed an easter egg in my page where it activated by someone typing in "up, up, down, down, left, right, left, right, B, A, enter" while they are on the page. I do not want a form on the page. is this even possible in php?

Many thanks

Jono

 

topr8




msg:4569927
 7:09 am on May 2, 2013 (gmt 0)

php is a server side technology, it cannot capture anything the user does.
i'm not a javascript guru but i imagine that is what you want to do what you desire.

jonorr




msg:4570126
 8:04 pm on May 2, 2013 (gmt 0)

awesome I will look into that.

Thanks

Readie




msg:4571668
 9:11 pm on May 7, 2013 (gmt 0)

As topr8 said, not the right forum, but...

Using the jQuery plugin ([jquery.com ]), this will do what you want to do. Just replace that alert with your easter egg code:

(function($) {
var sequence = [38, 38, 40, 40, 37, 39, 37, 39, 66, 65, 13];
var currentSequence = [];
$(document).ready(function() {
$(window).on('keydown', function(event) {
if(sequence[currentSequence.length] != event.which) {
currentSequence = [];
return;
}
currentSequence.push(event.which);
if(sequence.length == currentSequence.length) {
currentSequence = [];
alert('THA KONAMI CODE!');
}
});
});
})(jQuery);

I suggest using the jQuery plugin (Or a similar tool) for this sort of thing, as the keyboard "key codes" can vary between browsers, and jQuery normalizes them for you through .which

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