| Return value undefined from $.post
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neophyte
msg:4443877 | 5:17 am on Apr 22, 2012 (gmt 0) |
Hello All -
While I've been coding php for years, I'm a real noob at javascript/jquery and have been beating my head over this single function for almost 2 days.
I've cobbled together the valAgainstDataBase() function (shown below) from an example found online. All I need is a return value of TRUE OR FALSE which is echoed from ajax_works_v2.php.
However, all that I get is from my calling function is "undefined"
Here's the calling function:
function checkLoginForm()
{
var logn = valAgainstDataBase();
alert('return value: ' + logn);
}
Here's the function BEING CALLED that should return TRUE or FALSE:
function valAgainstDataBase()
{
$.post("ajax_works_v2.php", {username: $('[id=username]').val(),
password: $('[id=password]').val()},
function(data) {
return data;
})
}
The .php file is echoing correctly so I know the issue lies somewhere in valAgainstDataBase().
Can someone please show me the error of my ways?
Great appreciation to everyone in advance.
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shingokko
msg:4443881 | 5:51 am on Apr 22, 2012 (gmt 0) |
OK, the problem is that the callback function of the AJAX call is inside valAgainstDataBase thus the value returned from the function is not used. I think it would work if you change it to:
function valAgainstDataBase(callback) {
$.post("ajax_works_v2.php", { username: $('[id=username]').val(), password: $('[id=password]').val()}, callback);
}
function chestLoginForm() {
valAgainstDataBase(function(data) {
alert('return value: ' + data);
});
}
Hope this works!
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neophyte
msg:4444092 | 4:21 am on Apr 23, 2012 (gmt 0) |
Hey shingokko -
Thanks very much for your reply - indeed your first post in WebmasterWorld!
While your solution worked, it didn't work as I really needed it to (I need checkLoginForm to return the value of valAgainstDataBase to a prevoius function).
But it's okay - found a workaround that (while more verbose) does satisfy my need.
Thanks again!
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