Fotiman
msg:3890363 | 3:46 am on Apr 11, 2009 (gmt 0) |
Presumably, the ad code is using document.write to generate content on the page, which means you can't execute it after page load. I haven't tried this, but I think it will work if you do this instead of setting the innerHTML: var topleftloader = document.getElementById('topleftloader');
document.getElementById("topleft").appendChild(topleftloader); Then set the style to display: block.
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Rufal
msg:3890543 | 1:36 pm on Apr 11, 2009 (gmt 0) |
Thank you! That worked great. I have no idea whats happening or how a block style works, but since it solved my problem I am very happy.
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Fotiman
msg:3890593 | 4:08 pm on Apr 11, 2009 (gmt 0) |
First, by using appendChild, you are removing a node ('topleftloader') from your document and appending it to a different node ('topleft'). The result is that you don't duplicate the node as you would by setting the innerHTML of 'topleft'. You had display:none, which hides the element. display:block makes it visible as a block item (which is what a <div> element has by default).
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Codnes
msg:3902549 | 5:06 pm on Apr 28, 2009 (gmt 0) |
I'm having problems. What am I doing wrong this code:
<html>
<body>
<div id="topleft"></div>
</body>
<div id="topleftloader" style="display:none;">[ad jscript goes here]</div>
<script type="text/javascript">
var topleftloader = document.getElementById('topleftloader');
document.getElementById("topleft").appendChild(topleftloader);
</script>
</html>
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Rufal
msg:3902596 | 6:27 pm on Apr 28, 2009 (gmt 0) |
Quoting Fotiman: "Then set the style to display: block. " Your Display is set to "none" style="display:block;" Regards [edited by: Rufal at 6:29 pm (utc) on April 28, 2009]
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Codnes
msg:3902703 | 8:38 pm on Apr 28, 2009 (gmt 0) |
I did tried that too. The code doesn't want to still execute. >_<
<html>
<body>
<div id="topleft">Loading</div>
</body>
<div id="topleftloader" style="display:block;">[ad jscript goes here]</div>
<script type="text/javascript">
var topleftloader = document.getElementById('topleftloader');
document.getElementById("topleft").appendChild(topleftloader);
</script>
</html>
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Rufal
msg:3902744 | 9:24 pm on Apr 28, 2009 (gmt 0) |
It needs to go just before </body> not after. Try that
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Codnes
msg:3902758 | 9:35 pm on Apr 28, 2009 (gmt 0) |
Still not working. :( Can you paste the code that worked for you?
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Rufal
msg:3902809 | 10:30 pm on Apr 28, 2009 (gmt 0) |
ok, somewhere up in my content I have a : <CENTER>
<div id="partnerbox"></div>
</CENTER> Then towards the bottom content (before </body> ) I have: <div id="partnerboxloader" style="display:block;">{Lots of script text stuff here, unchanged from ad vendor}</div>
<script type="text/javascript">
var loader = document.getElementById('partnerboxloader');
document.getElementById("partnerbox").appendChild(loader);
</script> I actually have separate script snippets for each ad/script location, since I found that if I did it all in one large javascript nothing would render until the last one finished. By doing them separate I can make sure that my first ad location will start showing as soon as possible, then the next location, et cetera.
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