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|Cron Job Assistance|
I'm having a spot of bother with the cron job shown below.
What it suppose to do is:
1. Unzip the zip files in the given directory
2. Move the zip files into a zip directory
3. Move the log file after it has been unzipped into the logs directory.
The trouble I am having is that I'm not quite how to put this all together I've had a go, I've used the pipe command but I don't think that is the right command to use.
30 09 * * * /usr/bin/unzip /home/sites/test.domain.com/ex*.zip ¦ mv /home/sites/test.domain.com/ex*.zip /home/sites/test.domain.com/zips ¦ mv /home/sites/test.domain.com/ex*.log /home/sites/test.domain.com/logs
Put the commands that you want executed into a shell script, make sure that the script is executable and then call the script from your cronjob.
mv /home/sites/test.domain.com/ex*.zip /home/sites/test.domain.com/zips
mv /home/sites/test.domain.com/ex*.log /home/sites/test.domain.com/logs
and then in your cron file
30 09 * * * script.sh
Hope this works
Much appreciated for the feedback, and so quick as well, nice! :o)
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