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|select from multiple tables - same field name|
| 2:35 pm on Jan 10, 2003 (gmt 0)|
I have a number of tables ie, sales, number of customers, refunds.
each table is split up by months jan, feb, march etc.
I want to display all the months and then each table on a row, so along the top you have the months then below each month would be the appropiate figure from each table.
can i use something like select * from sales, customers where storeid=12345
then print out $jan, $feb, $March
I'm struggling on how to output the results cos there are going to be more than one field called january - how do get sales/january and customers/january
| 3:14 pm on Jan 10, 2003 (gmt 0)|
Are you looking for something like "select S.january, C.january, etc from Sales as S [some kind of] join Customers as C [using field] where storeid=1234"?
That's a very rough outline, but when you need to disambiguate filed names in a select on multiple tables, the 'as' keyword is your friend.
| 3:29 pm on Jan 10, 2003 (gmt 0)|
I don't know I just want to end up with ...
SALES JAN - 35%
SALES FEB - 50%
CUSTOMERS JAN - 456
CUSTOMERS FEB - 654
where sales and customers are the tables, Jan and feb are field names and numbers are the values of the fields.
I know I can just do
select * from sales where storeID=666
select * from custoers where storeID=666
but I have a lot of tables and wondered if I can do it all in one go?
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