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PHP Server Side Scripting Forum

    
if x contains y in php
simple in perl, can't find good php site
mdharrold




msg:1279993
 9:42 pm on Mar 7, 2002 (gmt 0)

I'm trying to learn PHP. Partly because of the responses in here [webmasterworld.com], partly because I want to.

In perl what I want would be:
if ($url =~ /http/)
{$url = $url;}
else
{$url = "http://$url";}

So what would be the PHP equivalent?

 

mdharrold




msg:1279994
 10:29 pm on Mar 7, 2002 (gmt 0)

I found a reasonable fix:
if (preg_match ("/http/i", "$url"))
{$url = $url;}
else {$url = "http://$url";}

Found it at zend [zend.com].

gethan




msg:1279995
 11:19 pm on Mar 7, 2002 (gmt 0)

> Perl: $url =~ /http/i
> PHP : preg_match ("/http/i", "$url")

preg - short for perl regular expressions.

What I miss most with php are reg expressions done the perl way ;) I just think that too much typing is involved. But then I had a short stint writing VB and found out what real pain is.

mdharrold




msg:1279996
 11:27 pm on Mar 7, 2002 (gmt 0)

I thought the same thing. Supposedly, PHP is easier to learn. It seems the language that would be easiest to learn would be the one with the least amount of required code.

DrDoc




msg:1279997
 10:02 am on Mar 16, 2002 (gmt 0)

/^http:\/\//

'cause what if the URL is "www.httpthing.com"?

And, what if the user typed in "http:/www.somesite.com" .. then it wouldn't work anyway ..

(In case you ask, yes, I'm only here to give you a hard time) ;)

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